Show an example using the ac method to factor a polynomial in the form: ax2 + bx + c where a is not equal to 1

i am tired of typing mathematical equations in yahoo answers so i'll just give the link to the web site





http://www.wtamu.edu/academic/anns/mps/m...





hope this helps you.





google keyword: factoring trinomials

Show an example using the ac method to factor a polynomial in the form: ax2 + bx + c where a is not equal to 1
If b=a+c


ax^2+bx+c


ax^2+ax+cx+c


ax(x+1)+c(x+1)


(x+1)(ax+c)
Reply:ax^2 +bx + c





ac method of factoring is to find out the factors of the product of x^2 coefficient, a and constant term c and such that their sum is equal to b, if ac is positive and if ac is negative their difference is equal to b





ex: 1 where ac is positive





3x^2 + 11x + 6





here a = 3 and c = 6 and b = 11





ac = 3*6 = 18





factors of 18 are 2*3*3 = 2*9





ac = 2*9 = 18





2+ 9 = 11 = b





the polynomial can be written as





3x^2 + 9x + 2x + 6





3x(x+3) +2(x+3)





=%26gt;(x+3)(3x+2)





ex:2 where ac is negative





2x^2 + x - 15





here a = 2 , c = -15 , b = 1





now product of factors of ac shoud be written as difference such that it equals b





ac = 30 = 6*5





b = 6-5





2x^2 + x - 15 =%26gt;





2x^2 +6x - 5x - 15





2x(x+3) - 5(x+3)





(x+3)(2x-5)