I will give you an example using A, B, and C:
A B C can make A, B, C, AB, AC, BC, and ABC.
AB = BA.
I would like to know the max number of combinations, and if possible(if you have time), all of the combinations. This is not for a homework assignment, I just want to know.
What is the max number of combinations using A, B, C, D, E, and F.?
2^6 - 1 = 63 ways.
Basically, you can either have the letter in the combination or not. So there are two possibilities for each letter. Using the General Counting Principle, you would multiply each of these possibilities, so 2*2*2*2*2*2 = 2^6. However, there is one combination where none of the letters are selected, so that's why you subtract 1.
edit: The above answerer has it now, only in a different way. Rodent, the order doesn't matter, and he wants to know how many ways you select a different number of letters.
Here's the list:
1. A
2. B
3. C
4. D
5. E
6. F
7. AB
8. AC
9. AD
10. AE
11. AF
12. BC
13. BD
14. BE
15. BF
16. CD
17. CE
18. CF
19. DE
20. DF
21. EF
22. ABC
23. ABD
24. ABE
25. ABF
26. ACD
27. ACE
28. ACF
29. ADE
30. ADF
31. AEF
32. BCD
33. BCE
34. BCF
35. BDE
36. BDF
37. BEF
38. CDE
39. CDF
40. CEF
41. DEF
42. ABCD
43. ABCE
44. ABCF
45. ABDE
46. ABDF
47. ABEF
48. ACDE
49. ACDF
50. ACEF
51. ADEF
52. BCDE
53. BCDF
54. BCEF
55. BDEF
56. CDEF
57. ABCDE
58. ABCDF
59. ABCEF
60. ABDEF
61. ACDEF
62. BCDEF
63. ABCDEF
Reply:I know this is a 10 month old "Answer", but how exactly did you look at this, I get 3600 combinations from A,B to F,E,D,C,B,A Report It
Reply:6+5+4+3+2+1= 21
no, no. how 'bout:
6 +6*5/(1*2) + 6*5*4/(1*2*3) +6*5*4*3/(1*2*3*4) +6*5*4*3*2(1*2*3*4*5) +1
6+15+20+15+6+1 = 63
Reply:6! which would be 6*5*4*3*2*1
which is 30*4*3*2
120*3*2
360*2
720?
Reply:AB
AC
AD
AE
AF
BC
BD
BE
BF
CD
CE
CF
DE
DF
A
B
C
D
E
F
ABCDEF
ABC
ABD
ABE
ABF
ACE
ACE
ACF
CDE
CDF
DEF
marguerite
Subscribe to:
Post Comments (Atom)
No comments:
Post a Comment