Simplify: A'BC'+AB'C'
I got this wrong on a test and I think my answer is right, so I would like to check it with you all.
In my expression, A' represents NOT A (for example).
I had C'(A'B+AB') = C'(A xor B)
Boolean Algebra: Simplify: A'BC'+AB'C'?
Your answer, C'(A xor B) looks right to me. What answer was given as the correct one for that question on your test?
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