g o f is onto C, but f is not onto B.
g is one-to-one, but g o f is not one-to-one.
(f o g is a function compostion, f composed with g)
Give an example of functions f:A----%26gt;B and g:B-----%26gt;C such that?
For the first one, say that A={0,1}, B={0,1}, and C={0}
Then if f(x)=0 and g(x)=0,
f(x) is not onto B (no x is such that f(x)=1 and 1 is in B)
but g o f is onto C (range of g o f = {0} = C)
For the second one, you can do it real easily: If C=B and |B| %26gt; |A| and g(x)=x, then certainly g is one-to-one, but (g o f) is not one-to-one since its range is larger than its domain.
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